Stainless
09-10-2009, 09:45 PM
Ok, so this is the original equation:
2π√(x+t) = 4
This is it "correctly" rearranged for x:
x= 4/π^2 -t
and this is what I got instead:
x= (4/2π)^2 -t
How, was from the oringal: Dividing both by 2π, Squaring both sides, then subtracting t from both sides. However what I thought would be right is quite far from what the book says is right. Anyone see where I went wrong?
2π√(x+t) = 4
This is it "correctly" rearranged for x:
x= 4/π^2 -t
and this is what I got instead:
x= (4/2π)^2 -t
How, was from the oringal: Dividing both by 2π, Squaring both sides, then subtracting t from both sides. However what I thought would be right is quite far from what the book says is right. Anyone see where I went wrong?