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  #81  
Old 08-29-2010, 06:58 AM
Irukanji Irukanji is offline
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Default Re: Noob Question's

Quote:
Originally Posted by fcknut View Post
Yup, and A, B, C, D, E and F are all exactly the same thing...

It's funny - it kinda looks like you have used chemdraw to draw the rings, then used MSpaint to wirte the letters... Any particular reason for that ?!
lol the whole thing is MSPaint, I used the "hexagon" shape to draw the rings. Is there any quick guides online which show what the ~ = - etc symbols mean?(i know = is double bond, - is normal, but im talking about the rest). Thanks.

Also, I forgot about this thread, lol. +1 for merge features.
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  #82  
Old 08-29-2010, 07:39 AM
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Default Re: Noob Question's

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Originally Posted by Irukanji View Post


The question is the picture.
It are a statements, and that statement is "cyclohexane."

Quote:
Originally Posted by Irukanji View Post


The question is in the picture.
Oh. Yuppers.

-R is "something hydrocarbon based," -X is "some halogen;" chlorine, fluorine, bromine, etc.

Look them all up on a periodic table. It's called a "p5 orbital" or something, but that's what they look like when they all share it. Sometimes, similar orbitals define a class of related compounds.

Yeah. "Equivalent" compounds. "Valence orbital" We our nations... ruled your continent.



Quote:
Originally Posted by Irukanji View Post


I guess the question is, what do the lines mean? Assume all the hexagons have position 1 at the top.
Okay. Should be rotatable unless you're comparing subbed positioning to another position on the molecule. "Everything's relative."

So...

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Originally Posted by Irukanji View Post
My guess is the lines are double bonds
Yup.

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Originally Posted by Irukanji View Post
If I think of more, I will probably draw some more fail pics...
I dunno, man, you're doing pretty good so far.
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  #83  
Old 08-29-2010, 08:07 AM
Irukanji Irukanji is offline
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Default Re: Noob Question's

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Originally Posted by JoePedo View Post
-R is "something hydrocarbon based," -X is "some halogen;" chlorine, fluorine, bromine, etc.
Quote:
Look them all up on a periodic table. It's called a "p5 orbital" or something, but that's what they look like when they all share it. Sometimes, similar orbitals define a class of related compounds.
Valency?

Quote:
Yeah. "Equivalent" compounds. "Valence orbital" We our nations... ruled your continent.
lolwut?

Quote:
I dunno, man, you're doing pretty good so far.
I can't fail all the time
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  #84  
Old 08-29-2010, 08:16 AM
Irukanji Irukanji is offline
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Default Re: The "lol, fuckin' n00bz" thread.

I haz a picture;



Ok I figured this out, it has something to do with the position of the atom relevant to the observer, ie. closer or further.
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Last edited by Irukanji; 11-15-2010 at 02:09 PM.
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  #85  
Old 08-29-2010, 08:17 AM
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Default Re: Noob Question's

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I can't fail all the time
your sure as hell trying















jks
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  #86  
Old 08-29-2010, 08:23 AM
Irukanji Irukanji is offline
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your sure as hell trying
I am mildly not amused.
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  #87  
Old 11-19-2010, 12:49 PM
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Default Re: The "lol, fuckin' n00bz" thread.

Quote:
It's hard to tell whether the ergoloids or the myristic allylbenzenes are more prosocial and positive in their effect and impact. One thing is clear, however; we must make them more prevalent in humanity, for the good of society and civilization.
The combination of the two is unfuckingbeatable for that as well as all purposes. Never again will I take LSD without first getting at least ~12+ grams of nutmeg in a few hours beforehand. I've been turning a lot of people on to the magic of nutmeg IRL, and the spirit of nutmeg seems to have some srs plans for me seeing as I decided to be receptive to it.

Also, JP I wanted to say that this is probably one of the better threads in existence and your fucking lovable style of guerrilla-revolutionary psychedelia has been a huge inspiration. I know you get it a lot. But damn, I just get stoked on life when I read your posts.

ALSOX2 - piracetam as an essential ingredient for maximum nootropy. I generally always include it in my cups of nutmeg coffee and it's always a markedly different experience in many ways to straight megz, but I'm still not entirely convinced as to the superiority of one to the other, if there is indeed such a distinction to be made and not just novelty to explore.
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  #88  
Old 01-29-2011, 08:02 AM
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Default Re: The "lol, fuckin' n00bz" thread.

This actually helped a lot.
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  #89  
Old 01-30-2011, 02:27 AM
Hydroponichronic Hydroponichronic is offline
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Default Re: The "lol, fuckin' n00bz" thread.

Oh, since someone bumped this thread, I'm adding some equations I derived:

The equation for percent dissociation of an acid as a function of pH:
Quote:
%=100*(10-pKa)/(10-pH + 10-pKa)
The equation for percent dissociation of a base as a function of pH:
Quote:
%=100*(10pKa)/(10pH+10pKa)
Remember that pka of a base is fourteen minus it's pkb (aka the pKa of it's conjugate acid).

Keep in mind some acids work by soaking up a OH- ion, and some bases work by soaking up a H+ ion, so the equation might relate to association, rather than dissociation.


This equation is useful when trying to figure out to what pH you need to get an aqueous solution of the compound to get it to precipitate or transfer into the nonpolar (this happens when the ionization is minimal). It's also useful when your target amine has both an acid and a base group, allowing you to calculate what the pH needs to be to ensure neither is ionized.

Morphine, for instance, has a tertiary amine with pKb 6.13, and a phenol with pKa 9.85. Plugging the pKa into the percent dissociation of an acid, and (14-pKb) into the ionization of an amine equation, set them equal, and solve for pH. We then see that at pH 8.86, both groups are only 9.3% ionized, meaning that %82.2 of the morphine is freebase and is available for solution in nonpolar solvent (though most nonpolar solvents will not dissolve much morphine).

Now, another set of equations, for those with weak acids and bases, who want to figure out pH as a function of concentration:

The equation for pH of a solution of a weak acid given Ka and concentration:
Quote:
pH=-log((Ka(4(conc)+Ka))1/2-Ka) - log(2)

The equation for pH of a solution of a weak base given Kb and concentration:

Quote:
pH=14+log((Kb(4(conc)+Kb))1/2-Kb) - log(2)
Oh, and be careful about what "log" you're using. In the above equations it's log base ten, aka: log10

Also, in the second set of equations I use Ka and Kb, not pKa and pKb.
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Last edited by Hydroponichronic; 01-30-2011 at 02:54 AM.
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